I need help denesting a radical
\[x=\sqrt{\frac{ 3 }{ 2 }-\frac{ \sqrt{5} }{ 2 }}\]
I did some with a plus sign but I don't know how to do it with a negative sign D;
Where on the equation the signs changes is my problem.
I'll give a hint : \(\large 3 - \sqrt{5} = \dfrac{1}{2} \left[6 - 2\sqrt{5}\right] \\\large = \dfrac{1}{2} \left[1^2 + \sqrt{5}^2 - 2\sqrt{5}\right] \\ \large = \dfrac{1}{2} \left( 1-\sqrt{5}\right)^2 \)
\[\sqrt{A \frac{ + }{ - }B}=\sqrt{1/2A + 1/2 \sqrt{A^2 - B^2}} \frac{ +}{ - }\sqrt{1/2A -1/2\sqrt{A^2-B^2}}\]
for \(\large \pm\) , you ma use below latex code : ``` \pm ```
$$\Huge a^2-2ab+b^2= (a-b)^2$$
I have to solve it by using the formula I posted
@ganeshie8 Please :o
I am trying to get x=1/2(-1-sqrt(5)) and x=1/2(1-sqrt(5))
my question was suppose to be x= +-
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