Question

Find the perimeter of the following shape, rounded to the nearest tenth:

Shape ABCD is shown. Point A is at negative 3, 5. Point B is at 1, 7. Point C is at 3, 3. Point D is at negative 1, 1.

9.8

16

17.9

24

Answer 1

do u have any fig

Answer 2

yea i do @nirmalnema
here

Answer 3

Okay

Answer 4

A=(-3,5)
B=1, 7.
C=3, 3
D=-1, 1.
NOW BY DISTANCE FORMULA U CAN FIND LENGTH OF SIDE
AB , BC ,CD ,DA
DISTANCE FORMULA=
\[\sqrt{(x1−x2)^{2}+(y1−y2)^{2}}\]

Answer 5

lengths are
AB= \[\sqrt{20}\]
BC= \[\sqrt{20}\]
CD= \[\sqrt{20}\]
DA= \[\sqrt{20}\]

Answer 6

\[\sqrt{20}=4.47\]
right

Answer 7

NOW PERIMETER = SUM OF ALL THE SIDE LENGTH
=\[\sqrt{20}+\sqrt{20}+ \sqrt{20}+ \sqrt{20}\]
=\[4\sqrt{20}\]
=4*4.47

Answer 8

YUP U R RIGHT

Answer 9

17.88

Answer 10

the answer is C right
because there is no 17.88

Answer 11

yup.

Answer 12

oh okay
Thank YOU

Answer 13

welcome..!!