Question

consider the sequence An=12An-1with a1=2 the closed form of An is
A.An=2+17^n-1
B.An=17n+19
C.An=2(17)^n-1
D.An=17n+2

Answer 1

can you find A2 ??

plug in n=2 in
\( A_n=12A_{n-1}\)

and use A1 = 2, to get A2

Answer 2

ok

Answer 3

@hartnn

Answer 4

so what did u get for A2 ?

Answer 5

24

Answer 6

thats correct.

now find the common difference 'd' = 2nd term -1st term = A2-A1 = ... ?

Answer 7

a2-a1=wouldnt it be 23?

Answer 8

sorry, i meant we have r = common ratio = A2/A1 = 24/2 =12

now we can directly use the formula
\(\Large a_n = a_1 r^{n-1}\)

here a1 = 2, r =12
just plug in!

Answer 9

bdw, none of the choices work

Answer 10

either question is incorrect, or the choices

Answer 11

ok

Answer 12

The fibonacci sequence is defined recurively by the following
a1=1
a2=1
an=an-1-an-2
A.true
b.false

Answer 13

@hartnn

Answer 14

next term is not the difference, its the sum.,
the correct one is :
\(a_n=a_{n-1}+a_{n-2}\)

Answer 15

so its false