How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 milliliters?
Molarity= mole/Volume
mole= Molarity* Volume
mole= mass/Molecular mass
so Molarity*volume= mass/Molecular mass
so mass= Molarity* Volume* Molecular mass
now put the values into this formula and get the final answer :)
Molarity= 0.75 M Volume= 500.0mL = convert to L by dividing this value by 1000 Molecular mass of NaCl you can find from periodic table
Number of Moles=Concentration(mol/dm^3)*Volume(dm^3) Change 500 ml unit to dm^3 by dividing by 1000 In your periodic table look for each elements atomic weight Na:23 Cl:35.5 NaCl:(23*1)+(35.5*1)=58.5 gram per mole Use Number of moles=Mass(g)/Molar Mass(g/mol)
thanks guys , this helped a lot
your most welcome :)
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