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Chemistry 21 Online
OpenStudy (anonymous):

How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 milliliters?

OpenStudy (somy):

Molarity= mole/Volume

OpenStudy (somy):

mole= Molarity* Volume

OpenStudy (somy):

mole= mass/Molecular mass

OpenStudy (somy):

so Molarity*volume= mass/Molecular mass

OpenStudy (somy):

so mass= Molarity* Volume* Molecular mass

OpenStudy (somy):

now put the values into this formula and get the final answer :)

OpenStudy (somy):

Molarity= 0.75 M Volume= 500.0mL = convert to L by dividing this value by 1000 Molecular mass of NaCl you can find from periodic table

OpenStudy (abmon98):

Number of Moles=Concentration(mol/dm^3)*Volume(dm^3) Change 500 ml unit to dm^3 by dividing by 1000 In your periodic table look for each elements atomic weight Na:23 Cl:35.5 NaCl:(23*1)+(35.5*1)=58.5 gram per mole Use Number of moles=Mass(g)/Molar Mass(g/mol)

OpenStudy (anonymous):

thanks guys , this helped a lot

OpenStudy (abmon98):

your most welcome :)

OpenStudy (somy):

\(\huge\cal\color {pink}{ You~ are~ welcome~ ❤ } \)

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