Question

If 12.03 kJ of heat are required to melt 36.0 grams of water, what is the heat of fusion of water?

2.99 kJ/mol

6.02 kJ/mol

12.04 kJ/mol

60.20 kJ/mol
@Somy
@Abhisar

Answer 1

Hello !

Answer 2

Can u calculate the moles of water in 36 grams ?

Answer 3

no :( am bad at chem
@Abhisar

Answer 4

Do u know the molar mass of water ?

Answer 5

18.02 @Abhisar

Answer 6

good !

Answer 7

@somy now am confused again

Answer 8

See it's simple, 12.03 kJ/mol required for 36 grams or 2 moles

Answer 9

Then for one mole how much heat is required ?

Answer 10

Define latent heat of fusion

Answer 11

so do i divide 12.03 by 36.0 @Somy @Abhisar

Answer 12

but it doesnt give me the answer i need

Answer 13

See the unit @Somy kJ/m = kJ per mole

Answer 14

mass= is in Kg
so change it to Kg

Answer 15

so = 36/1000= 0.036 kg

now u can use the formula

Answer 16

i got 0.299

Answer 17

probably @Abhisar im not having calculator atm

Answer 18

lol i think i confused everyone +_+ lets start it over

Answer 19

@somy i got the answer wrong :(

Answer 20

I think it should be B

Answer 21

how did u come up with it?

Answer 22

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
Then for one mole how much heat is required ?
\(\color{blue}{\text{End of Quote}}\)

Answer 23

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
See it's simple, 12.03 kJ/mol required for 36 grams or 2 moles
\(\color{blue}{\text{End of Quote}}\)

Answer 24

1 mole of H2O= 18

Answer 25

12.03/2 =

Answer 26

wait lol

Answer 27

@Abhisar now im confused
isn't Q= 12.03 ?

Answer 28

but they are asking for Latent heat of fusion

Answer 29

wait a sec
are they just indirectly asking for Q
and by bringing up 'fusion' they are confusing us? @Abhisar

Answer 30

@veronica.montanez are you taking Cambridge system?

Answer 31

@Somy no

Answer 32

hmmm @Abhisar take over this - i don't really get what they are asking for
coz for Latent heat of Fusion =number is real big

Answer 33

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
See it's simple, 12.03 kJ/mol required for 36 grams or 2 moles
\(\color{blue}{\text{End of Quote}}\)

Answer 34

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
Then for one mole how much heat is required ?
\(\color{blue}{\text{End of Quote}}\)

Answer 35

eat of fusion is the amount of heat energy required to change the state of a substance from solid to liquid.
Q=m*Delta f
Delta f unit is KJ/mol
36 grams is 2 moles of water.
Delta F= 12.04/2=6.02KJ per mole