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OpenStudy (anonymous):

Weather records show that the probability of rainfall in Florida in June is 0.86. What is the probability that it rains there in June at least 9 times in a decade? 0.26 0.41 0.22 0.58

OpenStudy (anonymous):

@taylorannbs @kohai

OpenStudy (anonymous):

During any one year, the probability of rainfall is 0.86; call this your success probability. The probability of failure (no rain) is then 1-0.86 = 0.14. This is a binomial probability, meaning for \(n\) observations, the probability that success occurs at least \(k\) times is equivalent to \[\large P(X\ge k)=\sum_{x=k}^n \binom nx p^x(1-p)^{n-x}\] Translated to this context, you want \[\large\begin{align*}P(X\ge9)&=\sum_{x=9}^{10}\binom{10}x(0.86)^x(0.14)^{10-x}\\ &=\binom{10}9(0.86)^9(0.14)^{10-9}+\binom{10}{10}(0.86)^{10}(0.14)^{10-10}\\ &=10(0.86)^9(0.14)+(0.86)^{10}\\ &\approx0.22 \end{align*}\]

OpenStudy (anonymous):

0.22 is wrong i got it wrong.

OpenStudy (anonymous):

0.41 is wrong also

OpenStudy (anonymous):

It's D 0.58

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