Question

The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?



1,040 cal

40 cal

270,000 cal

1.08 cal

Answer 1

Q=Mass*The latent heat of vaporization
Q=540*500=270000 Cal

Answer 2

Given \[500g\] water

Answer 3

Conversion factor
\[\frac{ 500 \cal}{ 1g}\]

Answer 4

Solve
\[500g \times \frac{ 540cal }{ 1g}= \]