Question

HELPP ME!!WILL AWARD ...What is the equation for a circle with center (2, -3) and radius of 6?

Answer 1

\[r^2 = (x - h)^2 + (y-k)^2\]

Answer 2

(x - h)^2 + (y - k)^2 = r^2 where (h,k) is the center and r is the radius
Substitute the center (h,k)=(0,2) and r = SR(6)
(x - 0)^2 + (y - 2)^2 = ((SR(6))^2
x^2 + y^2 - 4y + 4 = 6
x^2 + y^2 - 4y = 2

Answer 3

(x - 2)2 + (y + 3)2 = 6


(x - 2)2 + (y + 3)2 = 36


(x + 2)2 + (y + 3)2 = 36


(x - 2)2 + (y - 3)2 = 36

Answer 4

@tanya123 @nydr ^ that is the answer choices.

Answer 5

good to know:)

Answer 6

@nydr so which one is it?

Answer 7

(x-2)^2 + (y+3)^2 = 36

Answer 8

is the real one

Answer 9

so it would be x^2 - 4x +4 + y^2 + 6y + 9 =36
x^2 +y^2 -4x +6y +13-36
x^2 + y^2 - 4x +6y - 23 = 0