Question

@JungHyunRan

Answer 1

That's the rest

Answer 2

First part

Answer 3

\(\huge \color{blue}{First\ part}\)

\(\Large \color{red}{I.}\ 28=2(L+W)\\\Large \color{red}{II.}\ 28=2(L+W) \Leftrightarrow L+W=14\Leftrightarrow W=14-L\\\Large \color{red}{III.}\ 48=LW\\\Large \color{red}{IV.}\ 48=L(14-L) \Rightarrow L^2-14L+48=0\\\Large \color{red}{V.}\ L=\frac{14\pm \sqrt{14^2-4\times48}}{2} \Rightarrow L=6\ \ or\ \ L=8\)

Answer 4

\(\Large \color{red}{VI.}\ .L=6 \Rightarrow W=14-6=8\\\Large .L=8\Rightarrow W=14-8=6\\\Large \color{red}{VII.}\ do\ \ yourself\ \ :)\)

Answer 5

Thank yooou so much! Made an A! @JungHyunRan

Answer 6

:) glad to hear that

Answer 7

On step 2 at the end it says w=14-.. 14- what? I put 8 for some reason it doesn't let me view past that part. @JungHyunRan

Answer 8

Is l 6 or 8?

Answer 9

What did you write?

Answer 10

I wrote L = 6 when equation is +
L =8 when -

Answer 11

-_- no, L=6 wnhen - and L=8 when +

did you not check my answer?

Answer 12

Yeah I did and it said the opposite

Answer 13

\(\Large L=\frac{14+ \sqrt{14^2-4\times48}}{2}=\frac{14+2}{2}=8\\\Large L=\frac{14-\sqrt{14^2-4\times48}}{2}=\frac{14-2}{2}=6\)

Answer 14

@MelllB

Answer 15

Gotcha thank you

Answer 16

:)