What is the line of symmetry for the parabola whose equation is y = 3x2 + 24x - 1? x = -8 x = -6 x = -4
Again use \[\frac{ -b }{ -2a }\] I didn't tell you that you were finding the line of symmetry for the last problem, but now I think its necessary. Like I told you previously a= the first value in the equation provided and b= the second, etc
the line of symmetry is x = -4, and I will show you how to do that, ok?
you need to complete the square on the x terms in order to get this into graphing form. Rewrite like this:
\[y=(3x ^{2}+24x)-1\]and you will factor out the 3 since you cannot complete a square until the leading coefficient is 1. So now you have this:
\[y=3(x ^{2}+8x)-1\]Take half the coefficient on the x term (8) which is 4, square it (16) and add it to the inside of the parenthesis to complete the square, like this:
\[y=3(x ^{2}+8x+16-16)-1\]now move the -16 out of the parenthesis, but when you do, remember that when it is inside the parenthesis it is being multiplied by a 3, so it would look like this in application:
\[y=3(x ^{2}+8x+16)+(-16)(3)(-1)\]
now the parenthesis look like this because what's inside the parenthesis now is a perfect square binomial:
@IMStuck Now that I think about it, I only showed him how to find the vertex of the parabola. So, don't use the previous question for reference. Also IMStuck, I've been waiting for a hour or so for a question that I asked that I got the answer for, but am not sure if it is right. Mind helping out?
\[y=3(x+4)^{2}+(-16)(3)(-1)\]
my answer of -4 was correct; I forgot we were looking for the line of symmetry and was confusing it with another problem to find the y coordinate of the vertex. So -4 is still correct, and we wouldn't even have to go further with this unless we want to, because the line of symmetry is found on the x axis, and since the x coordinate of the parabola's vertex is -4, that is where the line of symmetry is.
HOWEVER, continuing on with your problem the whole equation for that parabola in graphing form is this:\[y=(x+4)^{2}+48\]
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