Question

factor 64c^2-49

Answer 1

@umangiasd
hmm...

Answer 2

As far as I know, \(x^2+y^2\) has no factors. :)

Answer 3

*no real rational factors.

Answer 4

Lol, wrote it wrong
\[x^2-y^2=(x+y)(x-y)\]
Gonna delete the mistake, thanks

Answer 5

Answer (8c-7)^2

Answer 6

Hmm...is that an answer to the above question, or is it a new question?
@dianaeshun

Answer 7

Above

Answer 8

Using @umangiasd 's formula
\(x^2-y^2=(x+y)(x-y)\)
We have:
\(64c^2-49\)
\(=(8c)^2-7^2\)
\(=(8c+7)(8c-7)\)
@forgiven94 @dianaeshun