Question

How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 grams of calcium metal?

Ca (s) + 2HBr (aq) yields CaBr2 (aq) + H2 (g)

1.11 liters
2.22 liters
2.81 liters
225 liters

Answer 1

@Abhisar

Answer 2

Number of Moles=Mass(g)/Molar Mass(g/mol)
Number of moles of Ca(s)=100/40.1=2.49
Mole ratio 1 mole Ca(s) reacts with 2 mole of HBr
2.49 mole of Ca(s) reacts with X mole of HBr
X=2.49*2/1=4.98
Number of Moles=Concentration*Volume
Volume=Number of Moles/Concentration
Volume=4.98/2.25=2.216 Liters

Answer 3

Thank you! soo much!

Answer 4

Your welcome :)