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A 9 V battery is hooked in series with two resistors. R1 = 75 , and R2 = 100 . A. The voltage is 9 V, so the current must be 1575A B. The total resistance is 25Q and the current is 0.05 A C. The total resistance is 175Q and the current is 0.09A D. The total resistance is 175Q and the current is 0.05A
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@Abhisar
Net resistance is series combo = R1+R2
So the resistance will be ?
D??
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thanks
Total resistance will be 175 and then use V=IR to find I which will be equal to 0.05A
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