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OpenStudy (anonymous):
9^(x+1)=27, can someone assist me with this i forgot how to do it cause i moved from the section.
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OpenStudy (anonymous):
ugh .. i wish i can help you on this but i forgot how too ....-.
OpenStudy (anonymous):
Its fine
OpenStudy (anonymous):
its -3/4
OpenStudy (precal):
|dw:1405629594765:dw|
OpenStudy (anonymous):
what im trying to do is solve for x, which is 1/2. i wanna know how i can get that number
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OpenStudy (precal):
there is a rule in mathematics that states if you can create the same base, you can solve for x using the powers only
OpenStudy (precal):
9 and 27 can be rewritten using the same base, do you know which base I am referring to?
OpenStudy (anonymous):
logarithm?
OpenStudy (anonymous):
i wanna know how i can get to x+1=3/2
OpenStudy (precal):
yes you can log both sides but it is easier to set it to the same base
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OpenStudy (precal):
logs are another approach
OpenStudy (anonymous):
so how do i solve this?
OpenStudy (precal):
well can you answer my question? can 9 and 27 have the same base? if so, what is it?
example 2 and 8 have the same base because 2^3 is also 8
OpenStudy (anonymous):
i dont think they can although 9*3 is 27
OpenStudy (precal):
how about 3? can you rewrite those numbers in exponential form using base 3?
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OpenStudy (anonymous):
no?
OpenStudy (precal):
3^2 is
3^3 is
OpenStudy (anonymous):
9 and 27 oh.. wow
OpenStudy (precal):
|dw:1405630199913:dw|
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