PLZ HELP!!!
@aum help
@thomaster @phi @myininaya plz help me
@jdoe0001 @cwrw238 @Luigi0210 @lacrosseplayer22 help me PLEZ
Just distribute and simplify. a * (b + c) = ab + ac
but i dont get radicals at all
the equation doesn't make sense to me. trust me I would help. mail me and ill try
well.. what did you get for \(\bf \sqrt{2}(3\sqrt{2}+\sqrt{18})?\)
i dont know
hmm have you covered square root adding yet? and maybe multiplication?
yes, but i didnt understand :(
If it would help try writing \(\Large \sqrt{2}\) as \(\Large 2^{\frac 12}\)
hmm... say for example... any idea on what \(\bf \sqrt{2}\times \sqrt{2}=?\)
\[\sqrt{4} ...?\]
yeap \(\bf \sqrt{2}\times \sqrt{2}=\sqrt{2\cdot 2}\implies \sqrt{4}\implies \sqrt{2^2}\implies 2\)
so the answer is 2...?
thus \(\bf \sqrt{2}(3\sqrt{2}+\sqrt{18}) \\ \quad \\ {\color{brown}{ 18\to 2\cdot 3\cdot 3\to 2\cdot 3^2}}\qquad thus \\ \quad \\ \sqrt{2}(3\sqrt{2}+\sqrt{{\color{brown}{ 18}}})\implies \sqrt{2}(3\sqrt{2}+\sqrt{{\color{brown}{ 2\cdot 3^2}}})\implies \sqrt{2}({\color{blue}{ 3}}\sqrt{2}+{\color{blue}{ 3}}\sqrt{ 2}) \\ \quad \\ \sqrt{2}({\color{blue}{ 6}}\sqrt{2})\implies ?\)
\[6\sqrt{4}...?\]
yeap which is \(\bf \sqrt{2}({\color{blue}{ 6}}\sqrt{2})\implies 6\sqrt{4}\implies 6\sqrt{2^2}\implies 6\cdot 2\)
so 12?
yeap
so the answer is 12?
so it is rational and equal to 12, which is answer choice C?
yes, notice the factoring of the 18 combines with the other term then the factors left, combine to 12
ok thank you
well.. 12 is a rational number yes, that is, you can express it as a "ration" or fraction 12/1
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