A health class takes a field trip to go canoeing. A canoe was paddled downstream with the current and traveled 45 miles in 5 hours. On its return trip, the canoe was going into the current and was paddled at the same rate. The return trip took 9.5 hours. The current was flowing at 2 miles per hour during both trips.

Question

anonymous · Answer

Part A  Write an equation that you could use to find the canoe’s speed, r, in miles per hour when it traveled with the current. Write another equation that you could use to find the canoe’s speed, r, in miles per hour when it traveled against the current.
Part B  Solve one of your equations from Part A to determine the canoe’s speed in still water in miles per hour.

anonymous · Answer

Help please

anonymous · Answer

the rate going was $\frac{45}{5}=9$ and the rate returning was $\frac{45}{9.5}=\frac{90}{19}$

anonymous · Answer

that makes 
if the rowing speed is $r$ then $r+2=9$ and $r-2=\frac{90}{19}$

anonymous · Answer

Thank you so much! I got it!

anonymous · Answer

great! not sure if it is right though.. .i had second thoughts