Question

PLEASE HELP????


Tristan says that solutions to radical equations are extraneous. Hadley says that solutions to radical equations are non-extraneous. Find an equation where Tristan is correct and a second equation where Hadley is correct. Using complete sentences, explain each step when solving to justify your examples.

Answer 1

@IMStuck @iPwnBunnies @iambatman

Answer 2

@precal

Answer 3

Okay. First of all do you understand the meaning of extraneous solution ?

Answer 4

yes i do

Answer 5

Great !

Answer 6

when you solve for x and then when you go to plug it in it does not equal the same solution as it said beofre

Answer 7

So I will give you one example for both persons and you find out another example

Answer 8

\[\large{\sqrt{x} = x-6}\]

\[\large{\implies x = (x-6)^2}\]

\[\large{\implies x^2 - 13x + 36 = 0}\]

\[\large{\implies x^2 - 9x - 4x + 36 = 0}\]

\[\large{\implies (x-9)(x-4) = 0}\]

\[\large{\implies x = 9,4}\]

Though, when you will check you will notice that x = 4 doesn't satisfy the main equation

Answer 9

Extraneous solution ^^

Answer 10

As for non extraneous solution:

\[\large{\sqrt{x+3} = 0}\]

\[\large{\implies x+3 = 0}\]

\[\large{\implies x = -3}\]

There is only one solution and this satisfies the main equation ....

Answer 11

@jenniferjuice, did you get these examples ?

Answer 12

yesssss i diddd

Answer 13

Great can you think of some more ?