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Chemistry 20 Online
OpenStudy (superhelp101):

What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C? 84.2 mm Hg 289 mm Hg 617 mm Hg 936 mm Hg

OpenStudy (superhelp101):

@asib1214

OpenStudy (somy):

PV= nRT

OpenStudy (dan815):

^noob

OpenStudy (asib1214):

you have given three things, you can find the fourth eaisly...btw the answer is 936mm Hg

OpenStudy (somy):

P= atm - after calculation u can convert it to m Hg V= Liter n= mole R= constant = 0.08206 T= Kelvin

OpenStudy (somy):

Celsius+ 273= Kelvin

OpenStudy (asib1214):

Given: n= 2.5 mol, V50 mol, T= 27C Required: Pressure in mm Hg solution: PV=nRT before you plugin the values i suggest you should convert C into Kelvins 27 + 273 = 300K Now rearrange the formula so that you are solving for P and it should be P=nRT/V

OpenStudy (somy):

put the values into the formula and get the answer :3

OpenStudy (asib1214):

p= 2.5mol X 8.314(L.KPa/K.mol) X 300K divide everything by 50L

OpenStudy (asib1214):

it shold look something like this

OpenStudy (superhelp101):

Thank you all for all you help!!

OpenStudy (asib1214):

|dw:1405662538096:dw|

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