Question

The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field.

Answer 1

Part A Write a system of two equations that could be used to find the length and width of the field. Let x represent the length of the field, and let y represent the width of the field.
Part B Solve the system of equations for x and y to determine the dimensions of the field.

Answer 2

the first one should be ok right
\[2x+2y=200\] or maybe even
\[x+y=100\]

Answer 3

so just the substitution method?

Answer 4

hold on you still need a second equation

Answer 5

don't they both work as two?!

Answer 6

The length of the field is 7 feet more than two times the width of the field

Answer 7

oh nvm

Answer 8

oh i have confused you
the perimeter is \(2x+2y=200\)i just made it easier and wrote \(x+y=100\) it is the same equation

Answer 9

oooh ok

Answer 10

how about translating
The length of the field is 7 feet more than two times the width of the field

Answer 11

addition

Answer 12

7ft + 2x = width of field ??

Answer 13

yeah i would say
\[x=2y+7\] i think

Answer 14

If i were you, I'd take the information contained in the problem statement, "The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field," choose variables to represent the length and width, and then write two equations that accurately represent the verbal statements. Only then should you consider how to solve this system of linear equations.

Answer 15

it really doesn't matter but they told you \(x\) is the length and \(y\) is the width
they are being annoying and telling you how to do it as if there is one method

Answer 16

@satellite73 tru tru

Answer 17

now that you have your two equations
\[x+y=100\\
x=2y+7\] you can solve

Answer 18

2x(7y+7)+2y=200 ?

Answer 19

accidentally added the x

Answer 20

yeah try again i think you will get it

Answer 21

2(7y+7)+2y=200
14y+14+2y=200

Answer 22

14+16y=200

Answer 23

i think one of those sevens should be a two

Answer 24

not \[2(7y+7)+2y=200 \] but rather
\[2(2y+7)+2y=200 \]

Answer 25

4y+14+2y=200
14+6y=200
6y=200-14=186 ?

Answer 26

6y=186

Answer 27

ok

Answer 28

y=31

Answer 29

looks good to me

Answer 30

x+31=186
x=155

Answer 31

hmmm

Answer 32

\[2x+2y=200\\
2x+2\times 31=200\]

Answer 33

it isn't \(x+y=200\) it is either
\[2x+2y=200\] or
\[x+y=100\]

Answer 34

awh the answers i came up with are wrong

Answer 35

really?

Answer 36

yeah
155+31=186
2(155)+2(31)=372

Answer 37

i get
\[x=69,y=31\]

Answer 38

wait i see the problem
you had \(x+31=200\) but is should have been \(x+31=100\)

Answer 39

ooh

Answer 40

where exactly was where i messed?

Answer 41

i dont see it

Answer 42

you wrote \[x+31=186\] i have no idea where that came from

Answer 43

it could have been either
\[x+31=100\] or
\[2x+2\times 31=200\] or easier still
\[x=2\times 31+7\]

Answer 44

OOOH okay i see it now

Answer 45

thank you so much for being patient with me!!

Answer 46

yw
good luck!