Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

tetraphosphorus, commonly known as white phosphorus, forms different compounds with chlorine depending on the amount of chlorine present. If chlorine is limited, phosphorus trichloride is formed. If there is an excess of chlorine, phosphorus pentachloride is formed. Write balanced equations for the two reactions of white phosphorus with chlorine.

OpenStudy (somy):

how about trying yourself first?

OpenStudy (anonymous):

I got 2P4 + 2Cl2 -> 4PCl + P4 for the first equation

OpenStudy (somy):

read the question once again

OpenStudy (anonymous):

wouldn't there be excess phosphorus if chlorine is limiting?

OpenStudy (somy):

There are 2 types of products possible when P reacts with Cl

OpenStudy (anonymous):

oh oops its PCl3

OpenStudy (somy):

\(PCl_3\) or \(PCl_5\)

OpenStudy (anonymous):

1 second I'll re-balance

OpenStudy (somy):

\(PCl_3\) - when chlorine is limiting \(PCl_5\) - when chlorine is in excess

OpenStudy (anonymous):

ok so 2P4 + 6Cl2 -> 4PCl3 + P4

OpenStudy (somy):

2P4 + 6Cl2 -> 4PCl3 + P4 why do u have P4 in product side?

OpenStudy (somy):

in each case only 1 product is formed!

OpenStudy (anonymous):

because there's excess tetraphosphorus isn't there?

OpenStudy (anonymous):

@Somy

OpenStudy (somy):

No

OpenStudy (somy):

Its excess CHLORINE

OpenStudy (somy):

NOT phosphorus

OpenStudy (anonymous):

why though because chlorine is limiting

OpenStudy (somy):

look when P and Cl react this is ADDITION reaction

OpenStudy (somy):

when chlorine is in limited amount - the product formed will be PCl3 but when there is enough chlorine -the product formed will be PCl5

OpenStudy (anonymous):

so there's nothing else besides that on the product side?

OpenStudy (somy):

5 bonds- is maximum number of bond P can make so in case if Cl is less - it'll make 3 bonds with Cl if Cl is more then its enough to use all 5 last shell electrons for bonding with Cl

OpenStudy (somy):

yes.

OpenStudy (anonymous):

so it's: P4 + 6Cl2 -> 4Pcl3 P4 + 10Cl2 -> 4PCl5

OpenStudy (somy):

yup

OpenStudy (anonymous):

Thank you! How would I design an experiment to verify this?

OpenStudy (anonymous):

i would take molCl<molP4 and then combine right?

OpenStudy (somy):

hmm i don't really know about experiment part but well in one case u'll take limited amount of Cl while in other case you'll take excess amount of Cl

OpenStudy (anonymous):

thanks :)

OpenStudy (somy):

no problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!