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Chemistry 7 Online
OpenStudy (anonymous):

how do i design a synthesis reaction lab?

OpenStudy (anonymous):

@Australopithecus @Abmon98 @superhelp101

OpenStudy (australopithecus):

Depends on what you are synthesizing, your starting material, the synthetic pathway you are following.

OpenStudy (australopithecus):

If you just want a general synthesis laboratory I cant give you a list of things you would likely need if you wanted to do a wide range of reactions

OpenStudy (anonymous):

I need to design a lab where I can show how excess chlorine reacts with tetraphosphorus to create PCl5 in this reaction: P4 + 10Cl2 -> 4PCl5

OpenStudy (australopithecus):

What are your starting materials?

OpenStudy (anonymous):

I have to design it all from scratch. I can use whatever materials I'd like.

OpenStudy (anonymous):

@Abmon98

OpenStudy (australopithecus):

So you are trying to achieve phosphorus pentachloride, P4 + 6Cl2 → PCl5 So essentially this reaction. P4(s) + 6Cl2(g) → 4PCl3(l) PCl3(l) + Cl2(g) → PCl5(s)

OpenStudy (australopithecus):

Oops, P4(s) + 6Cl2(g) → 4PCl3(l) 4PCl3(l) + Cl2(g) → PCl5(s)

OpenStudy (anonymous):

but I need to design a lab that could be performed to verify each synthesis reaction including my initial masses, my hypothesis, and possible problems. And then I need to explain how my experiment would confirm the conservation of matter for each reaction.

OpenStudy (australopithecus):

Well you need to know what reaction you are conduction to even start.

OpenStudy (anonymous):

2 reactions. One excess chlorine and one limiting chlorine. P4 + 6Cl2 -> 4PCl3 and P4 + 10Cl2 -> 4PCl5

OpenStudy (anonymous):

one lab for each

OpenStudy (australopithecus):

Do you have scientific literature or is this a highschool class? I mean you can just devise a method yourself I suppose but it will require math.

OpenStudy (australopithecus):

seems like a pretty simple reaction, essentially you would reflux white phosphorous and bubble chlorine gas through it

OpenStudy (anonymous):

Just a high school class haha

OpenStudy (australopithecus):

I already kind of have an idea of how to do this reaction, so essentially you need to look up msds of white phosphorous and find an inert solvent to dissolve it in. Essentially you would want to do this reaction under inert atmosphere as water reactions with PCl5, and there is water in our atmosphere

OpenStudy (anonymous):

so add the two in water?

OpenStudy (australopithecus):

Read.

OpenStudy (anonymous):

I dont know what an inert solvent is and I don't know what you mean by an inert atmosphere

OpenStudy (australopithecus):

Water reacts with both your desired product and your intermediary producing an unwanted side product

OpenStudy (sweetburger):

https://www.youtube.com/watch?v=lqLlmXmMiFQ

OpenStudy (australopithecus):

Inert atmosphere is one that is not reactive

OpenStudy (australopithecus):

So N2 or more nobel gases

OpenStudy (australopithecus):

it doesnt interfere with the reaction, since our atmosphere contains water it will react with your reactants and form biproducts resulting in a lower yield which is not desired

OpenStudy (australopithecus):

Essentially you cant use water as a solvent for your white phosphorous

OpenStudy (australopithecus):

you can just say you are using a tank of Cl2

OpenStudy (australopithecus):

I will draw out a diagram, you can just ignore the inert atmosphere part and just say there will be a reaction between water in the atmosphere and your reactants/intermediary (look up the reactions or figure them out yourself).

OpenStudy (australopithecus):

Ok here is a diagram of the set up you need. i.imgur.com/nsihSNW.png Key things to note, -You would dissolve all of your white phosphorous in some solvent that is non reactive, check the MSDS for white phosphorous and thank the Canadian government. (You could just say a non-polar solvent). -You should look up the colour of your product and reactant this can be used to indicate when your reaction is complete (Check MSDS or wikipedia) -Perform this in a fume hood and probably explain why. -You would want to use excess chlorine because it is in gas form. -I assume you dont want to isolate your product since you just want to observe the reaction. So I wont get into that. You might see your product crash out of solution again check its solubility (msds sheet). Not much more help I can give you, anways i have to go take care.

OpenStudy (australopithecus):

oops you wont want a rubber stopper at the top of the reflux aparatus you will want it on the other neck of the two neck round bottom flask

OpenStudy (australopithecus):

ok I'm done

OpenStudy (australopithecus):

Also give me a medal I have earned it :l spent like an hour on this.

OpenStudy (anonymous):

hahaha thank you! And I get exactly what you're saying now but I feel like that'd be slightly advanced for my class haha

OpenStudy (australopithecus):

Oh and a side note the amount you use is abstract, just pick an arbitrary amount to dissolve it in. Yeah well I dont know how else you would synthesize what you are asking, it isnt really that advanced.

OpenStudy (australopithecus):

you can just glaze over the details doesnt matter, but just explain the glassware you will use and say you will use a non polar solvent and make a concentration of a certain molarity. then you will just bouble Cl2 from a pressurized tank into it while refluxing the solution. Not really that hard. If you are confused about figuring out what the limiting reagent is just google limiting reagent in youtube.

OpenStudy (australopithecus):

Your hypothesis will just be the colour it changes to, and if there is a precipitate etc.

OpenStudy (australopithecus):

Look up the msds sheets for your product and reactant

OpenStudy (australopithecus):

it will tell you information about its solubility and colour

OpenStudy (australopithecus):

just use enough white phosphorous or something to make a 1M solution idk

OpenStudy (anonymous):

@Australopithecus how would this confirm the conservation of matter?

OpenStudy (australopithecus):

It would confirm it by giving you close to the predicted amount of PCl5 produced from the P4 based on the reaction equation used, if you were to extract all the solvent from the reaction and assume that the reaction goes to completion. As this would make it clear that no new matter was created or lost. You would see either a loss because of transfer, and extraction process, and due to the fact that the reaction might not go to completion but still. Also, if this was a closed system (which it is not), you could show that it remains the same mass even after the reaction has taken place.

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