312 mL of 1.50 x 10-2 M NaOH is used to titrate 225 mL of a monoprotic acid of unknown concentration to reach the equivalence point. What is the molarity of the acid?
Answer

1.50 x 10-2 M

4.68 x 10-3 M

2.08 x 10-2 M

1.05 x 10-3 M

Question

312 mL of 1.50 x 10-2 M NaOH is used to titrate 225 mL of a monoprotic acid of unknown concentration to reach the equivalence point. What is the molarity of the acid?
Answer
		
1.50 x 10-2 M
		
4.68 x 10-3 M
		
2.08 x 10-2 M
		
1.05 x 10-3 M

asib1214 · Answer

C_1 X V_1 $$C_1 X V_1 = C_1 X V_2$$

asib1214 · Answer

you have given three known values, you can find the fourth using C1 X V1 = C2 X V2

abmon98 · Answer

Write down a balanced chemical equation:
NaOH+HNO3-->Na(NO3)+HOH
Number of Moles=Concentration(mol/dm^3)*Volume(dm^3)
Look at the mole ratio.

asib1214 · Answer

before you plugin the given values, you should convert ml into L
and 312ml turns into 0.312L and 225ml turns into 0.225L

asib1214 · Answer

now plugin the given values in the formula and solve for C2 like this

asib1214 · Answer

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