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integrate with respect to x (e^x-e^-x)^2
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\[\int(e^x-e^{-x})^2~dx=\int(e^{2x}-2+e^{-2x})~dx\]\[\int(e^{2x})~dx-\int(2)~dx+\int(e^{-2x})~dx=\frac{e^{2x}}{2}-2x-\frac{e^{-2x}}{2}+K\]\[\int(e^x-e^{-x})^2~dx=\frac{1}{2}(e^{2x}-4x-e^{-2x})+K\]
Thank you so much @D3xt3R :D
You're welcome ;)
Thank you @eliassaab
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