Question

based on the ratio of moles of reactants in each case, predict the product of each trial of your experiment (PCl3 or PCl5) using your chosen initial masses. Explain your reasoning and show any calculations.
for my first trial I've chosen:
70.91gCl2 (1 mol Cl2)
247.79gP4 (2 mol P4)

for my second trial I've chosen:
272.73gCl2 (3 mol Cl2)
247.79gP4 (2 mol P4)

Answer 1

@Abhisar @sweetburger

Answer 2

@Abmon98

Answer 3

oh the reactions are:
P4 + 6Cl2 -> 4PCl3
and
P4 + 10Cl2 -> 4Pcl5

Answer 4

i am sorry man i dont quite get your question you can ask someone else :/

Answer 5

@Abmon98 I think I just need to find the grams or mols of PCl3 or PCl5 according to my initial amounts.

Answer 6

@dsood15 how does those 2 reactions help to predict products
P4 + 6Cl2 -> 4PCl3
and
P4 + 10Cl2 -> 4Pcl5

Answer 7

@dsood15 i realised a mistake
272.73/Molar Mass=3
272.73/3=90.91
Cl2 (35.5*2)=71 g

Answer 8

@Abmon98 how did you go from 90.91 to the next line?

Answer 9

@dsood15 Mass/Molar mass=number of moles
in the second trial 272.73gCl2 (3 mol Cl2)
272.73/M.M=3
M.M=272.73/3=90.91 as the molar mass so how is that possible?

Answer 10

Ah I see... well thank you anyway I'll try and figure it out

Answer 11

your welcome :)

Answer 12

good luck :)