Question

NEED HELP
suppose a parabola f(x)has its vertex at (0,1)and its zero atx=-2and x=2 then f(x)equals
A.1-1/4x^2
B.4-x^2
C.x^2-1
D.x^2-4

Answer 1

@Nurali can u help me ?

Answer 2

If the two roots are 'p' and 'q', the equation of the parabola is:
y = a(x-p)(x-q) where a is a constant that can be determined by substituting the vertex.

Answer 3

ok can u help me solve it ?

Answer 4

Here the two roots are 2 and -2.
That means (x-2) and (x - -2) are factors.
That is (x-2) and (x+2) are factors.
Multiply (x-2) and (x+2). What do you get?

Answer 5

96

Answer 6

i plugged it in my calculator thats what i got

Answer 7

Multiply the factors (x-2)(x+2).
Use the identity: (a+b)(a-b) = a^2 - b^2 or use FOIL method to multiply it out.

Answer 8

i got D as the answer is that correct

Answer 9

Can you show the work that got you that answer?

Answer 10

(x-2)(x+2)=96 ,,,,,,,,, x^2-4=96

Answer 11

That 96 is wrong.

Just multiply (x-2)(x+2) first.

Answer 12

i got 96 again

Answer 13

what did u get

Answer 14

Don't use your calculator. multiplying (x-2)(x+2) will not be a number. It will be a quadratic function.

Answer 15

x^2+2x+-2+4

Answer 16

Actually it is: x^2 + 2x -2x - 4
Simplify it.