Question

What polynomial has roots of -6, -4, and 1?

Answer 1

x3 - 9x2 - 22x + 24

x3 - x2 - 26x - 24

x3 + x2 - 26x + 24

x3 + 9x2 + 14x - 24

Answer 2

Since it has the roots -6, -4, and 1
You write it like this
(x+6)(x+4)(x-1)
Now multiply

Answer 3

\(x=\{-6, -4, 1\}\to \large
\begin{cases}
x=-6\to {\color{brown}{ x+6}}=0\\
x=-4\to {\color{brown}{ x+4}}=0\\
x=1\to {\color{brown}{ x-1}}=0
\end{cases}\qquad thus
\\ \quad \\ \bf
({\color{brown}{ x+6}})({\color{brown}{ x+4}})({\color{brown}{ x-1}})=0\implies ({\color{brown}{ x+6}})({\color{brown}{ x+4}})({\color{brown}{ x-1}})=\textit{original polynomial}\)

Answer 4

ok thanks!

Answer 5

x3 - 9x2 - 22x + 24

x3 - x2 - 26x - 24

x3 + x2 - 26x + 24

x3 + 9x2 + 14x - 24

Answer 6

so is it B? @Venny @jdoe0001

Answer 7

Hmm nope! Sorry for the late reply, can you show me how you got b?

Answer 8

Its ok @Venny its too late.

Answer 9

Oh, sorry :(

Answer 10

Its ok!