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Algebra
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OpenStudy (genny7):
Which of the following values of x is in the solution set of 2|x + 4| > 14?
A.
x = 0
B.
x = 1
C.
x = –3
D.
x = –12
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OpenStudy (jdoe0001):
\(\large {2|x + 4| > 14\implies |x + 4| \cfrac{\cancel{ 14 }}{\cancel{ 2 }}
\\ \quad \\
|x+4|>7\to
\begin{cases}
+(x+4)>7
\\ \quad \\
-(x+4)>7
\end{cases} }\)
OpenStudy (anonymous):
thats wrong too ._.
OpenStudy (anonymous):
lol we both messed up XD
OpenStudy (genny7):
so you were wrong chucho?
OpenStudy (anonymous):
mhmm :C
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OpenStudy (anonymous):
still working on it tho
OpenStudy (genny7):
So how do you solve it then!
OpenStudy (jdoe0001):
you'd solve each case or scenario, thus 2 scenarios, thus 2 values for "x"
I don't see anything wrong above though
OpenStudy (anonymous):
one sec almost done
OpenStudy (anonymous):
Got it! :D
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OpenStudy (anonymous):
you ready for my awesome explanation? Replace X with one of the numbers, and check if its true!
OpenStudy (anonymous):
2[-12+4>14
2*8
16>14
OpenStudy (genny7):
Uhhh I'm lost Chucho!
OpenStudy (anonymous):
kk lemme explain slower
OpenStudy (anonymous):
|dw:1405720698631:dw|
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OpenStudy (anonymous):
does this help? just go from top to bottom :3
OpenStudy (genny7):
Yeah, but thats not one of the answers???
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