Question

What is the solution set of |2x + 1| > 5?
A.
{x|1 < x < –3}
B.
{x|–1 < x < 3}
C.
{x|x > 2 or x < –3}
D.
{x|x < 2 or x > –3}

Answer 1

I think its C

Answer 2

x>2
Set up the − portion of the ± solution. When solving the − portion of an inequality, flip the direction of the inequality sign.
2x+1<−(5)
Multiply −1 by the 5 inside the parentheses.
2x+1<−5
Since 1 does not contain the variable to solve for, move it to the right-hand side of the inequality by subtracting 1 from both sides.
2x<−1−5
Subtract 5 from −1 to get −6.
2x<−6
Divide each term in the inequality by 2.

x<−3
The solution to the inequality includes both the positive and negative versions of the absolute value.
x>2 or x<−3
The solution is the set of values where x>2orx<−3.
x>2∪x<−3

Answer 3

definatly c

Answer 4

Yep

Answer 5

http://www.quickmath.com/webMathematica3/quickmath/inequalities/solve/basic.jsp#c=solve_stepssolveinequality&v1= |2x+%2B+1|+%3E+5

Answer 6

Kay Thanks guys! :)

Answer 7

np

Answer 8

whats that website for?

Answer 9

just put your questions in there and it will answer them

Answer 10

ok thanks! :)