Question

Can you help me with a couple of questions?

Answer 1

Question 1. Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).
Question 1 options:
1) y = x + 7
2) y = -3x + 3
3) y = x + 3
4) y = -3x + 7

Question 2. Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2)
Question 2 options:
1) y = - x - 6
2) y = - x - 14
3) y = 3x - 6
4) y = 3x - 14

Answer 2

What is the slope of the line y = -3x + 12 ?

Answer 3

Do you know the answers?

Answer 4

I am not allowed to give out answers but if you want to learn I may be able to help.

Answer 5

Ok so how do I answer the first one?

Answer 6

In y = mx + b, m is the slope. Therefore,
in y = -3x + 12 what is the slope?

Answer 7

-3 right?

Answer 8

correct. slope = -3
Parallel lines have the same slope.
So the equation of the line is y = -3x + b.
We need to solve for b.
Since the line passes through the point (-1, 6),
put y = 6 and x = -1 into y = -3x + b and solve for b.

Answer 9

So 6=3+b?

Answer 10

6=3+b
subtract 3
3 = b

y = -3x + b
y = -3x + 3

Answer 11

Follow the exact same method for the second problem.

Answer 12

So the answer for the first question is y=-3x+3

Answer 13

Yes.

Answer 14

For the second question just rearrange the equation 3x - y = -3 so that it is in the form y = mx + b.
3x - y = -3
add y
3x = y - 3
add 3
3x + 3 = y or
y = 3x + 3

Slope = the coefficient of the x term which is 3.
Parallel lines have the same slope.
y = 3x + b
It passes through the point (4,-2)
put x = 4 and y = -2 and solve for b
Then put b back in y = 3x + b to get your answer.

Answer 15

Can you please tell me the answer for the second one because I have to leave soon