Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X:

The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees and angle CBA measures 56 degrees.

What is the measure of angle ACB?

32°

60°

28°

16°

Answer 1

so u need my help hmmm :P

Answer 2

yes

Answer 3

hmm im jk i'll help :P

Answer 4

*cough cough*answers

Answer 5

:)

Answer 6

hahaha :P = )

Answer 7

ok back to work :P

Answer 8

angle BOA = 156 (given)
angle OAB = angle OBA (base angle, isos triangle)
= (180-156)/2 (angle sum of triangle)
= 12
angle OAC = 90 (tangent perpendicular to radius)
So, angle BAC = 12+90 = 102

Angle BCA = 180 - angle CBA - angle BAC (angle sum of triangle)
= 180 - 32 - 102 =?

Answer 9

46

Answer 10

yes : )

Answer 11

so............................

Answer 12

wait so what i did something wrong hold on :P

Answer 13

xD

Answer 14

hmmm @9ix9ix what's the "intercepted arc" angle?

Answer 15

@jdoe0001 the 2 line that coss in circle

Answer 16

why?

Answer 17

uh..............no

Answer 18

._.

Answer 19

any ideas?

Answer 20

its -28

Answer 21

positive..

Answer 22

negative ....wth

Answer 23

hehehe

Answer 24

:( ugh

Answer 25

you might be thinking

Answer 26

hmmm wait a sec

Answer 27

oh

Answer 28

56/2=28

Answer 29

28=88

Answer 30

-???? =60? or na

Answer 31

\(\bf \textit{inscribed angle}=\cfrac{\textit{intercepted arc}}{2}\implies 2\times \textit{inscribed angle}=\textit{intercepted arc}\)

Answer 32

56=88 O.o

Answer 33

hmmm need to dash... anyhow.... once you find that angle value for that arc
then you can just find the angle for the other arc and use the -> http://www.mathwarehouse.com/geometry/circle/images/power-of-point/far-arc-near-arc-formula-picture-small.png

Answer 34

i am CON-FU-SED

Answer 35

CONFUSED..........

Answer 36

@9ix9ix

Answer 37

@nikato need ur help

Answer 38

i couldnt figure it out srry :(

Answer 39

:)

Answer 40

so im calling some1 who might

Answer 41

ok :)

Answer 42

Im sorry i wanted to help i just couldn't figure out how :(

Answer 43

FREAK he got off stay here for 30 sec

Answer 44

:(

Answer 45

lifes hard xD

Answer 46

it is: P

Answer 47

i need help. my last qjuestion left

Answer 48

@Venny

Answer 49

@iPwnBunnies

Answer 50

@sourwing

Answer 51

goingg with 28 :/

Answer 52

Did you find the measure of arc XA yet?

Answer 53

no

Answer 54

IT WASNT 28

Answer 55

:( THANKS FOR UR HELP

Answer 56

<XBA is the inscribed angle of the intercepted arc XA

Answer 57

So
<XBA =1/2 (arcXA)
56=1/2 (arcXA)
So arcXA=112