Question

CAN SOMEONE PLEASE HELP ME WITH THIS ONE QUESTIONS???
Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution.

x plus a over ax = b over x
Part 1. Show all work to solve for x in the equation and check the solution.

Answer 1

@satellite73

Answer 2

hmm let me look do you have anymore information you could give me?

Answer 3

\[\frac{x+a}{ax}=\frac{b}{x}\]?

Answer 4

Yes

Answer 5

Not reeally, all i know that anextraneous solution is a solution of a simplified version of an equation that does not satisfy the original equation

Answer 6

what are you supposed to do? find \(a\) and \(b\) with no solution ?

Answer 7

THey want me to plug in numbers in a and b

Answer 8

that has an extraneous solution

Answer 9

@satellite73 is awesome and super smart :) ill leave y'all alone :)

Answer 10

you could make them both 1
that wouldn't have a solution
but i am not sure what it is really askign

Answer 11

\[\frac{x+1}{x}=\frac{1}{x}\] has no solution

Answer 12

my teacher told me to plug in values into the equation and find extraneous solution but im confused

Answer 13

being simple minded i made \(a=b=1\)

Answer 14

You would have to cross multiply after?

Answer 15

yes

Answer 16

Okay, one second, im going to write it down on paper

Answer 17

so would it be x(x+1)= x1?

Answer 18

yes

Answer 19

What about when you solve it? would it be 0?

Answer 20

yes it would

Answer 21

can you show me the steps though?

Answer 22

you would ge t
\[x^2+x=x\\
x^2=0\\
x=0\] but that is not a solution

Answer 23

oh ok, thanks

Answer 24

and \(0\) in not a solution to the original equation because you cannot have a zero in the denominator

Answer 25

oh

Answer 26

So is it okay, if i use these steps to write it down?

Answer 27

sure why not?

Answer 28

Okay, thank you very much for the help