How many ways are there to choose a committee of 5 people from a group of 15 people?
How do you solve this what is the equation?
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terenzreignz (terenzreignz):
15C5
Like, fifteen, choose five. ^_^
You know the formula for nCr?
OpenStudy (anonymous):
no I dont
terenzreignz (terenzreignz):
You know what "factorial" means?
OpenStudy (anonymous):
yes
terenzreignz (terenzreignz):
Okay, good. Then the formula for nCr is as follows:
\[\Large _nC_r = \frac{n!}{r!\cdot (n-r)!}\]
Just plug in :)
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OpenStudy (anonymous):
is n 5 and 4 15?
terenzreignz (terenzreignz):
What do you think? ;)
in general, n should be the larger number.
terenzreignz (terenzreignz):
Did you get your answer?
OpenStudy (anonymous):
is 3,003
terenzreignz (terenzreignz):
That's right ^^
Remember, that's what you do whenever you're asked how many ways you can pick r distinct members from a set of n.
nCr.
Good job :)
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OpenStudy (anonymous):
why can't you use nPr
terenzreignz (terenzreignz):
Good question. nPr
\[\Large _nP_r = \frac{n!}{(n-r)!}\]
is used for when ORDER matters.
For instance, if the question were how many ways we can ARRANGE five members from a group of 15 people in a ROW, then the answer would involve nPr instead.