@Kainui
The percent yield for the following reaction carried out in carbon tetrachloride solution is 80.0%. Br2+Cl2=2BrCL a. What amount of BrCl is formed from the reaction of 0.025 mol Br2 with 0.025 mol Cl2? b. What amount of Br2 is left unchanged?
The second part can be done if first part is known ,
So it looks like our first question is, is there a limiting reagent?
Yes , look at the second question yes
Are you saying you only need help with part a, and the second part you are fine to do on your own?
I searched this up on intenet i have one method My sir gave a different method , I am confused , my sir's method i am not getting it . but the answer arrived by this method is correct And the intenet method i am getting it , but the answer is incorrect , Shall i show both the methods , and see which method is wrong
Sure that sounds good, then we can pinpoint where the problem is.
This looks like good reasoning to me. Are you looking to find your answer in amount of mols or grams?
|dw:1405759160541:dw| But only 80 % react So, 231*80% |dw:1405759423925:dw| |dw:1405759277152:dw|
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