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Chemistry 19 Online
OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

The percent yield for the following reaction carried out in carbon tetrachloride solution is 80.0%. Br2+Cl2=2BrCL a. What amount of BrCl is formed from the reaction of 0.025 mol Br2 with 0.025 mol Cl2? b. What amount of Br2 is left unchanged?

OpenStudy (anonymous):

The second part can be done if first part is known ,

OpenStudy (kainui):

So it looks like our first question is, is there a limiting reagent?

OpenStudy (anonymous):

Yes , look at the second question yes

OpenStudy (kainui):

Are you saying you only need help with part a, and the second part you are fine to do on your own?

OpenStudy (anonymous):

I searched this up on intenet i have one method My sir gave a different method , I am confused , my sir's method i am not getting it . but the answer arrived by this method is correct And the intenet method i am getting it , but the answer is incorrect , Shall i show both the methods , and see which method is wrong

OpenStudy (kainui):

Sure that sounds good, then we can pinpoint where the problem is.

OpenStudy (kainui):

This looks like good reasoning to me. Are you looking to find your answer in amount of mols or grams?

OpenStudy (anonymous):

|dw:1405759160541:dw| But only 80 % react So, 231*80% |dw:1405759423925:dw| |dw:1405759277152:dw|

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