Question

If (1+3+5+...+a)+(1+3+5+..+b)=(1+3+5.....c), where each set of parentheses contains the sum of consecutive odd integers as shown such that- (1) a+b+c=21 (2)a>6 if G=Max{a,b,c} and L=Min{a,b,c} then
(A)G-L=4 (B)b-a=2 (C)G-L=7 (D)a-b=2

Answer 1

@ikram002p @hartnn @ganeshie8 hlp

Answer 2

@dan815

Answer 3

pls hlp

Answer 4

@hartnn hlp

Answer 5

y no 1 is replying?

Answer 6

cos it is a hard problem

Answer 7

yes it is

Answer 8

@satellite73

Answer 9

G-L=7 cannot be the answer cause odd-odd is even

Answer 10

have you gotten this far :

\[\large (a+1)^2 + (b+1)^2 = (c+1)^2\]

?

Answer 11

ya

Answer 12

yes

Answer 13

the problem simplifies to solving pythagorean triples :
\[\large x^2 + y^2 = z^2\]

\(x+y+z = 24\)

\(x \gt 7\)

Answer 14

ok

Answer 15

a,b,c will be max when a=b=c

Answer 16

G={7,7,7}

Answer 17

pls reply

Answer 18

@kainui

Answer 19

x+y+z =24
x^2+y^2=z^2

only 6,8,10 satisfies this

Answer 20

so,
a,b,c = 5,7,9

which gives b-a=2

Answer 21

Also,
G= 9, L=5
so, G-L also = 4

Answer 22

@hartnn great job man :) Genius

Answer 23

=D

Answer 24

ganeshie solved most of it!

Answer 25

:)

Answer 26

@hartnn how to take G

Answer 27

and L

Answer 28

G is max of (5,7,9)
maximum among them is 9
so, G is 9

Answer 29

L is min (5,7,9)
minimum among them is 5, so L=5

Answer 30

OK

Answer 31

awwww =D

Answer 32

Thnx @ganeshie8 and @hartnn

Answer 33

:@

Answer 34

lol, i just saw a>6 :P

Answer 35

so,
actually

a=7, b=5, c= 9

Answer 36

and
a-b =2

Answer 37

G-L still remains 4

Answer 38

nice relationship :D

Answer 39

YES I WAS JUST THINKING THAT