Write the expression as the sine, cosine, or tangent of an angle. sin 9x cos x - cos 9x sin x
Recall your Sine Angle Sum Identity:\[\Large\rm \sin \color{orangered}{\alpha}\cos\color{royalblue}{\beta}+\sin\color{royalblue}{\beta} \cos\color{orangered}{\alpha}=\sin(\color{orangered}{\alpha}+\color{royalblue}{\beta})\]
Woops I should have posted the Angle Difference Identity,\[\Large\rm \sin \color{orangered}{\alpha}\cos\color{royalblue}{\beta}-\sin\color{royalblue}{\beta} \cos\color{orangered}{\alpha}=\sin(\color{orangered}{\alpha}-\color{royalblue}{\beta})\]
And we were given:\[\Large\rm \sin \color{orangered}{9x}\cos\color{royalblue}{x}-\sin\color{royalblue}{x} \cos\color{orangered}{9x}\]Understand how to simplify it down using the identity?
Not really
So the formula\[\Large\rm \sin \color{orangered}{\alpha}\cos\color{royalblue}{\beta}-\sin\color{royalblue}{\beta} \cos\color{orangered}{\alpha}=\sin(\color{orangered}{\alpha}-\color{royalblue}{\beta})\]is telling us that when we have this configuration, we can write it as sine of, and subtract the angles. So with our problem:\[\Large\rm \sin \color{orangered}{9x}\cos\color{royalblue}{x}-\sin\color{royalblue}{x} \cos\color{orangered}{9x}\]We can apply this formula and write it as:\[\Large\rm \sin(\color{orangered}{9x}-\color{royalblue}{x})\]It can be simplified a tiny bit from there though.
Sin 8x
Yes.
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