Question

trig substitution, medal and fan

Answer 1

so when substituting i get ((6tan(t))^3)/(sqrt(6tan(t))^2+36)

Answer 2

working the denominator i get sqrt(36tan^2(t)+36)

Answer 3

36sqrt(tan^2(t)+1)

so far i right?

Answer 4

yes

Answer 5

then use pythagorean identity so 36sec^2(t)

Answer 6

this is for the denominator so all together i have int (tan^3(t)sec^2(t)dt)/(36sec^2(t))

Answer 7

x= tan(x) and dx=sec^2(x)