Find the value
x = 5 on number 5
and I think 8 is 48
@gswag98: Kindly help the person asking the question to find his/her own answers. This is not a test of your ability to find the answers, but rather of your ability to help someone else learn how to find his/her own.
In the first problem, the length of line segment AB PLUS the length of line segment BC comes to the length of line segment AC. What are the lengths of segment AB and segment BC in terms of x? Adding together both lengths in terms of x and equating the result to the given length of AC (20) should enable you to calculate x.
I MEANT PLUS
@helloeveryonee : Please involve yourself in this discussion. Share your thoughts. Ask questions.
so the reason why AB + BC = 20 is that (3x - 10) + (2x + 5) = 20 then u add those together first add the x's and then the numbers then you get 5x - 5 = 20 then what do you do next?? @helloeveryonee
Heller??? R U THERE!!! @helloeveryonee
yes @gswag98
i was trying to understand it
That'd be the perfect reason for asking some more questions of your own.
did u understand what I said?? @helloeveryonee
ok so @mathmale he or she's closed the question and is offline now
"so the reason why AB + BC = 20 is that (3x - 10) + (2x + 5) = 20 then u add those together first add the x's and then the numbers then you get 5x - 5 = 20 then what do you do next??" Let's re-write this a bit: "Given that the lengths of line segments AB and BC, when added together, equal a total of 20 units, then (3x-10) plus (2x+5) also add up to 20. Add 3x-10 to 2x+5 and set the result equal to 20. Sovle for x."
and for 5x - 5 = 20 x should equal 5
@helloeveryonee: It's your privilege to close a question if you wish to, but since both gswag98 and I spent a significant amount of time helping you, the least you could have done would be to let us know that you were leaving. I tend to give more help to students who seem to appreciate my help.
tbh idk y he or she would close the question and now be offline
Only @helloeveryonee can answer that. :(
what answer his or hers own question @mathmale
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