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What reduction half-reaction happens when zinc reacts with nickel(II) chloride? Zn(s) + NiCl2(aq) ZnCl2(aq) + Ni(s)
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Zn(s) + NiCl2(aq) --> ZnCl2(aq) + Ni(s)
@Australopithecus @sweetburger
@Abmon98
I think it's Ni(s) --> Ni2+(aq) + 2e− but I want to make sure I'm right
The oxidation state of an uncombined element is zero. \[Zn(s) + NiCl2(aq)\rightarrow ZnCl2(aq) + Ni(s)\] Zn(s)-->Zn+2(aq)+2e- Ni(+2)+2e--->Ni
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oh so it's Zn(s) --> Zn2+(aq) + 2e−
yes thats right
Ni(+2)+2e--->Ni
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