343 /64 x (4/7)^2 - 5/12
Do you know BODMAS?
\[\frac{ 343 }{ 64 } \times \left( \frac{ 4 }{ 7 } \right)^{2} - \frac{ 5 }{ 12 }\]
what does BODMAS stand for @Lena772
Brackets over Division Multiplication addition subtraction
So you solve the equation in that order
i did i got \[\frac{ 5483 }{ 3124 }\]
but it is wrong :(
the answer is somehow 4/5
Did you find the value of the second term before doing anything else?
you mean the number with the exponent? did i do that first? yes
@Lena772
Yes thats what i meant. Hmmm
(343/64) * 0.32653061224 - (5/12)
(5.359375*0.32653061224)-(5/12)
What im lost!!!!!
(1.74999999997)-(5/12)
(1.74999999997)-(0.41666666666)
where did you get those numbers from?
GO Lena! ~
All I did was convert them to decimals
Your answer is 1.33333333331. I don't know who told you it was 4/5.
thats the answer is the book is 4/5
Then put the answer in the book.
@mathmale can you help?
@tHe_FiZiCx99 can probably help you.
@Lena772 I hope @tHe_FiZiCx99 can help me.... maybe they know why the answer is 4/5
\(\ \Large \sf \frac{ 343 }{ 64 } \times \left( \frac{ 4 }{ 7 } \right)^{2} - \frac{ 5 }{ 12 } \) \(\ \sf \dfrac{343}{64} * \dfrac{16}{49} - \dfrac{5}{12} \implies \dfrac{5488}{3136} - \dfrac{5}{12} = \dfrac{65856}{37632} - \dfrac{15680}{37632} = \dfrac{50176}{37632} \) That's a big number u_u" using a calculator you still get 1.333.. 4/5 isn't correct.
However, this does simplify to 4/3.
\(\dfrac{343}{64} \times \left( \dfrac{4}{7} \right)^{2} - \dfrac{5}{12} \) \(= \dfrac{343}{64} \times \dfrac{16}{49} - \dfrac{5}{12} \) \(= \dfrac{343}{\cancel{64}~4} \times \dfrac{\cancel{16}~1}{49} - \dfrac{5}{12} \) \(= \dfrac{343 \times 1}{4 \times 49} - \dfrac{5}{12} \) \(= \dfrac{343}{196} - \dfrac{5}{12} \) \(= \dfrac{343 \times 3}{196 \times 3} - \dfrac{5 \times 49}{12 \times 49} \) \(= \dfrac{1029}{588} - \dfrac{245}{588} \) \(= \dfrac{784}{588}\) \(= \dfrac{196 \times 4}{196 \times 3}\) \(= \dfrac{4}{3}\)
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