Question

Integrate by parts

Answer 1

Did you solve it or give it a try ?

Answer 2

is it okay if i let u as x62 and dv as lnx @vishweshshrimali5 ?

Answer 3

its x^2

Answer 4

im solving it. =)

Answer 5

Well there is no problem in that :)

Answer 6

Just remember that you would have to calculate v

Answer 7

yes. okay wait. haha

Answer 8

\[\large{v = \int dv = \int \ln x dx}\]

Can you calculate that integral ?

Answer 9

Thus, I would suggest to use this instead:

\[\large{u = \ln x; dv = x^2 dx}\]

\[\large{\implies du = \cfrac{dx}{x}; v = \cfrac{x^3}{3}}\]

Answer 10

yeah suggestion's good. i'll try that

Answer 11

Sure take your time

Answer 12

Here is the formula for quick reference:

\[\large{\int u \ dv = uv - \int v \ du}\]

Answer 13

my answer is x^3/3 lnx - 1/9 x^3 +c

Answer 14

Perfect

Answer 15

Great work !

Answer 16

yey thank you so much!!