Chemistry
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OpenStudy (anonymous):
@Abhisar
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OpenStudy (anonymous):
Please help me , i am badly in need for help
OpenStudy (anonymous):
Do you know balancing in redox reactions
OpenStudy (anonymous):
Balance the following Redox reaction:-
\[FeSO_4 +KMNO_4 + H_2SO_4 \rightarrow FE_2(SO_4)_3 + MNSO_4 +H_2O +K_2SO_4\]
OpenStudy (anonymous):
@vishweshshrimali5 help
OpenStudy (anonymous):
I just have a problem in figuring out their oxidation states
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OpenStudy (vishweshshrimali5):
Fe = +2
Mn = +7
( in LHS)
OpenStudy (anonymous):
Yes but how???
OpenStudy (vishweshshrimali5):
Well try the basic method of calculating OS
OpenStudy (anonymous):
For FeSO4 what it would just give me an example i will do the rest
like
x-8 + ... =0
OpenStudy (vishweshshrimali5):
Yeah
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OpenStudy (anonymous):
what will be in the OS for sulphur
OpenStudy (anonymous):
is there any rule , i am confused
OpenStudy (somy):
break them up to ions first
OpenStudy (anonymous):
Ok wait , i will tell you what i have a problem with
OpenStudy (anonymous):
How will you find oxidation state of the elements in FeSO4
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OpenStudy (anonymous):
I know oxygen is always -2 right?
OpenStudy (somy):
oh
OpenStudy (anonymous):
i know your tutorial
OpenStudy (somy):
is it not clear?
OpenStudy (somy):
Well look
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OpenStudy (anonymous):
Can you do this one please
OpenStudy (anonymous):
ok
OpenStudy (somy):
FeSO4
OpenStudy (somy):
O= oxidation state always -2
OpenStudy (anonymous):
yes
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OpenStudy (somy):
Fe = +2
OpenStudy (somy):
why is it +2?
OpenStudy (anonymous):
why
OpenStudy (anonymous):
yes
OpenStudy (somy):
thats because oxidation state of \(SO_4\) is -2!
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OpenStudy (somy):
overall sum of oxidation states HAS to be 0 here
so if SO4 is -2
then Fe has to be +2
so that the final answer is 0
-2+2= 0
OpenStudy (somy):
do u get so far why Fe is +2?
OpenStudy (anonymous):
SO4 is x-8 =0 so sulphur must have +8 right
OpenStudy (somy):
i can explain in different way if u want
no
OpenStudy (anonymous):
yes go ahead
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OpenStudy (somy):
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