Question

This also i can't solve... Two vehichles p and Q,moving at the same speed are acted upon by equal braking forces until they stop.If the mass of P is four times that of Q,the ratio of the distance travelled by P to that travelled by Q is?
@Abhisar

Answer 1

Do u have the answer key ?

Answer 2

answer key?

Answer 3

don't know...

Answer 4

Ok let's see,
\(\sf F=ma\), now if force is same or constant then \(\sf a\propto \frac{1}{m}\)

Answer 5

\(\sf v^2=u^2-2as\), since the vehicles are braked until they stop, there final velocity v will be 0.
Now,
\(\large \sf s=\frac{u^2}{2a}\)

Answer 6

So,
\(\huge \sf s_p=\frac{u^2}{8a}, s_q=\frac{u^2}{2a}\)

Answer 7

Where, S\(_p~and~S_q\) are the distance travelled by p and q. Now can u find the ratio ?

Answer 8

yes...4:1

Answer 9

\(\huge\checkmark\)

Answer 10

Thank you...

Answer 11

Solving with energy is faster.
Since initial KE ratio is 4:1, then work done by the friction force must also be 4:1.
Since the magnitude of the force is the same, then the distance it must act is also in a 4:1 ratio.

Answer 12

ok...got it...

Answer 13

\(\huge\sf\color{green}{\text{✌ﾟ\(\ddot\smile\) ✌ﾟ}}\)