Question

Simply Algebra.

Answer 1

How would you split:\[\frac{ e^{2x} }{ 1+e^x}\]
into
\[\frac{ e^x }{ 1+e^x }-e^x\]

Answer 2

Not making sense.
\[\frac{ e^{2x} }{ 2 }?\]

Answer 3

yes ugh need @Data_LG2 he knows it better than me use him

Answer 4

he is way better I told him you need help

Answer 5

Looks like a conjugate base type of deal or a simple algebra split.

Answer 6

he is not here so use @jaceypoo they are better at this

Answer 7

or @heyimrick

Answer 8

\( \Large
\frac{ e^{2x} }{ 1+e^x} = \frac{ e^{x}e^x }{ 1+e^x} = \frac{ e^{x}(e^x+1-1) }{ 1+e^x} =
\\ \Large
\frac{ e^{x}(e^x+1) }{ 1+e^x} - \frac{ e^{x} }{ 1+e^x} = e^x - \frac{ e^{x} }{ 1+e^x}
\)

Answer 9

The negative I am looking for is the e^x

Answer 10

So just use the +1 instead.

Answer 11

Thank you very much!

Answer 12

Pull the negative sign out.

Answer 13

You are welcome.