Question

how do I solve this for x...55.5= -0.3476x^2+10.948x-23.078

Answer 1

subtract 55.5 from both sides.
divide both sides by 0.3476.
Solve the quadratic.

Answer 2

that will be 0= -0.3476x^2+10.948x-78.578

Answer 3

@Compassionate ...using the quadratic formular I'm getting an undefined answer.

Answer 4

55.5 = 0.3476x^2 + 10.948x - 23.078
subtract 55.5 from both sides:
0 = 0.3476x^2 + 10.948x - 78.578
divide both sides by 0.3476:
0 = x^2 + 31.496x - 226.059
x^2 + 31.496x - 226.059 = 0
use quadratic formula to solve for x.

Answer 5

\( \Large
x = \frac{-31.496 \pm \sqrt{31.496^2 - 4(1)(-226.059)}}{2} = ?
\)

Answer 6

this is -0.3476x^2

Answer 7

ok..let me calculate it

Answer 8

The coefficient of x^2 in your original posting is +0.3476 not minus.

Answer 9

yea..i made a mistake it is suppose to be minus

Answer 10

You can always go back and edit the post.

Answer 11

Then the equation will be: x^2 - 31.496x + 226.059 = 0

\(
\Large
x = \frac{31.496 \pm \sqrt{(-31.496)^2 - 4(1)(226.059)}}{2} = \\ \Large
x = \frac{31.496 \pm 9.368}{2} = \frac{40.864}{2}, \frac{22.128}{2} = ?
\)

Answer 12

20.432,11.064

Answer 13

Yes.

Answer 14

Round the answers If they ask you to do so. Otherwise leave it up to 3 decimals because the original problem has coefficients up to 3 decimal places.