A student solved the equation 6s – 10 = 2 + 3s + s and got s = –4. His work shown below is his check for this problem. Which statement best applies to the work shown? http://media.education2020.com/evresources/2003-03-04-00-00_files/i0170000.jpg A. His check does not work, thus s = –4. B. The work in his check is all correct, thus s = –34. C. The work in his check is all correct, thus s = –4. D. His check does not work, thus http://media.education2020.com/evresources/2003-03-04-00-00_files/i0170001.jpg
@robtobey
@DiotropicInventor
@SolomonZelman
Well choice A even without looking at the problem itself is silly, because if the check doesn't work, then s can't be -4. For B... check is correct, but it doesn't mean that s=-4, because all the check did is ─ proved that `s ≠ -4` C is also wrong, because the Check worked, but `s ≠ -4` I would go with D
If I am understanding "check doesn't work" correctly.
thank you
Well that fact of the matter is that s = 6. For any value of correct value of s, when plugged into the original equation, the LHS has to equal the RHS.
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