Question

@Abhisar
. A car of mass 1000 kg experiences a net force of 9500n while decelerating from 30m/s to 15.9m/s How far does it travel while slowing down?

Answer 1

F=ma
---> a =F/m

Now use the Third equation of motion to calculate distance. Take a=-F/m

Answer 2

So a =-9.5 m/s^2

Answer 3

What's the third equation of motion

Answer 4

\(\large\sf v^2=u^2+as\)

Answer 5

Refer this if it's not showing up
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Answer 6

We have two v and no u

Answer 7

V=final velocity (15.9 in this case)
U=initial velocity (30 in this case)

Answer 8

I got 68m but that's not an answer on the multiple choice

Answer 9

temme the answer choices

Answer 10

31 34 41 37

Answer 11

I think ur calculation is wrong. I am getting 34m

Answer 12

Recheck ur calculation

Answer 13

Got 34 this time thanks