At how many points does the graph of the function below intersect the x-axis?

y = 25x^2-10x+1

(picture) http://i.imgur.com/46qg57D.png

Question

At how many points does the graph of the function below intersect the x-axis?

y = 25x^2-10x+1

(picture) http://i.imgur.com/46qg57D.png

aum · Answer

First step: Factor 25x^2-10x+1

anonymous · Answer

(5x-1)^2

anonymous · Answer

it s2nd order eq..and x has max power of two..so it has two solution and so it will cross x-axis twice..as per no of solutions.

anonymous · Answer

1

aum · Answer

Yes.  How many different roots are there for the equation (5x-1)^2 = 0 ?

anonymous · Answer

the discriminanat equals 0 there fore there is one point that it intersects

aum · Answer

(5x-1)^2 = 0
The left hand side is a perfect square.  
Therefore it has one root with a multiplicity of 2.
It will intersect (or in this case, just touch) the x-axis just once.

solomonzelman · Answer

$\normalsize\color{blue}{ \rm   25x^2-10x+1   }$  is similar  (in terms of common sense)  to

$\normalsize\color{blue}{ \rm   x^2-10x+25   }$

anonymous · Answer

https://www.google.com/?gws_rd=ssl#q=25x%5E2+-10x+%2B1