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OpenStudy (anonymous):
Help me plez? the line that passes through (-2,0) and has a slope of 5 in point slope form
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OpenStudy (anonymous):
do you need a graph or the equation?
OpenStudy (anonymous):
the equation
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
woud it be y=8x+3??
OpenStudy (anonymous):
I mean y=-8x+3
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OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
y-y1=m(x-x1)
OpenStudy (anonymous):
so was it right or wrong?
OpenStudy (anonymous):
it was not correct
OpenStudy (anonymous):
whoops sorry that was my answer to the previous question
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OpenStudy (anonymous):
ah ok
OpenStudy (anonymous):
you should get something like y=5x+10
OpenStudy (anonymous):
so the answer for the line that passes through (-2,0) and has a slope of 5 in point slope form is y=5x+10?
OpenStudy (anonymous):
y-0=5(x+2)
y-0=5x+10
y=5x+10
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
another question: the line with a slope of -8 and a y intercept of 3 (in slope intercept form)
OpenStudy (anonymous):
would it come out to y=-8x+3
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
actually no
OpenStudy (anonymous):
okay thanks also How do I write a equation for: the horizontal line that passes through (-2,6)
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OpenStudy (anonymous):
wait srry about that ignore the previous message
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
the horizontal line equation is just y=6
OpenStudy (anonymous):
can u show how u got that? plez
OpenStudy (anonymous):
Whenever you want the equation of a
horizontal line it is always the y value.
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OpenStudy (anonymous):
same thing for the vertical line if you want the x value.
OpenStudy (anonymous):
so (-2,6) is in the form of (x,y)
OpenStudy (anonymous):
Ahh I see thanks
OpenStudy (anonymous):
Use the point-slope form linear equation: y+4=-4(x-2)
Rewrite this equation in slope-intercept form.
OpenStudy (mayaal):
slope intercept form:y=mx+b
m=slope
(x,y)=point
b=y-intercept
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OpenStudy (mayaal):
just solve the above equation for y
OpenStudy (mayaal):
y=-4x+4
OpenStudy (mayaal):
did u get it?
OpenStudy (anonymous):
ur a life saver.. how do I write it in standerd form
OpenStudy (mayaal):
this is the standard form
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OpenStudy (anonymous):
then how do I write it in slope intercept form?
OpenStudy (mayaal):
y=-4x+4
OpenStudy (anonymous):
so its written the same way both times?
OpenStudy (mayaal):
yes.
OpenStudy (anonymous):
thanks a lot. what is the x-intercept of this line?
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OpenStudy (mayaal):
ur wm:)u plug in 0 for y and then solve for x
OpenStudy (anonymous):
so it would be (0,-4)?
OpenStudy (mayaal):
no,its (0,1)
OpenStudy (anonymous):
can u show me how u got that?
OpenStudy (mayaal):
y=-4x+4
0=-4x+4
-4=-4x
-1=x
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OpenStudy (anonymous):
for the y intercept I got (0,8) is that right?
OpenStudy (mayaal):
no,its (0,4),and sorry,the x-intercept is(1,0).
OpenStudy (anonymous):
so at the end it would be 1=x?
OpenStudy (mayaal):
yes.u r correct:)
OpenStudy (anonymous):
lol ur the best! Im almost done. What is the equation in standard for of a perpendicular line that passes through(5,1)?
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OpenStudy (anonymous):
are u still there?
OpenStudy (mayaal):
yes,i have to submit an assignment by 5pm so im trying to do my last question.sorry for the late reply:)
OpenStudy (anonymous):
its okay go ahead and finish ur assignment
OpenStudy (mayaal):
i don't understand ur question
OpenStudy (anonymous):
Use the point-slope form linear equation: y+4=-4(x-2)
What is the equation in standard for of a perpendicular line that passes through(5,1)?
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OpenStudy (mayaal):
y=1/4x-1/4 is the perpendicular line's equaton in slope intercept form
OpenStudy (anonymous):
:0 I have to write it in standard form.. and show work dude ur seriously the best :)
OpenStudy (mayaal):
y+4=-4(x-2)
the slope of this line is -4,so the slope of the perpendicular line is 1/4.
y-y1=m(x-x1)
y-1=1/4(x-5)
y-1=1/4x-5/4
y=1/4x-5/4+1
y=1/4x-1/4
OpenStudy (mayaal):
r u still confused?
OpenStudy (anonymous):
nope u really helped :DD
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OpenStudy (anonymous):
what is the x intercept of the perpendicular line?
OpenStudy (mayaal):
(1,0)
OpenStudy (anonymous):
can u plez show me how u got that mayaal?
OpenStudy (mayaal):
sure.i substituted 0 for y,and then solved the equation to find x.
OpenStudy (anonymous):
I wish I can u a medal.. what is the equation in standard form of a parallel line that passes through (0,2)