Question

HELP!! Use the point-slope form linear equation: y+4=-4(x-2) What is the equation in standard form of a parallel line that passes through (0,-2)?

Answer 1

Equation of a line in point-slope form:
\((y-y_1)=m(x-x_1)\)
where m=slope, \((x_1,y_1)\) is a point through which the line passes.

Answer 2

sorry Im still lost

Answer 3

Can you find the slope of the given line (which is also the slope of the line you are looking for)?

Answer 4

I need help. Im lost :/

Answer 5

I believe the slope is -4

Answer 6

That is correct, and this corresponds to "m" in the point-slope form of the formula.
Now you will have to substitute \(x_1,y_1\) = (0,-2) into the point slope form of the equation.

Answer 7

can u set it up for me?

Answer 8

It's already done in my the equation of my first post.
You will have to substitute
m=-4
\(x_1\)=0,
\(y_1\)=-2
into the equation and simplify as you wish.

Answer 9

You can post your result if you're not sure.
I'm sure someone will be glad to look it over and check it for you, as I am logging off to grab a bite! :(

Answer 10

What is the equation in standard form of a parallel line

Answer 11

@sourwing can u help me plez

Answer 12

Heres wat I have so far if its correct.. y-1-2=4(x-0)
y+2=4x

Answer 13

Not exactly,
it should read:
\(y-(-2)=-4(x-0)\)
which translates to:
\(y+2=-4x)\)
or
\(y=-4x-2)\)