@Abhisar
A 12.0-g ball is placed in a slingshot with a spring constant of 200 N/m. The ball is stretched back 0.500 m. The slingshot is aimed straight up, then fired. What is the maximum height that the ball will reach?

Question

@Abhisar 
A 12.0-g ball is placed in a slingshot with a spring constant of 200 N/m. The ball is stretched back 0.500 m. The slingshot is aimed straight up, then fired. What is the maximum height that the ball will reach?

anonymous · Answer

F= Kx http://en.wikipedia.org/wiki/Hooke%27s_law and use the weight as an opposing force(friction is neglected).

akohl · Answer

So f would be .5*2000 which is 1000 how does that give me the height

akohl · Answer

I mean 100

akohl · Answer

The force of gravity is mg but that's not 100

anonymous · Answer

|dw:1405894458997:dw|
get the resultant force and use the equation.
|dw:1405894832755:dw|
get the terminal velocity 
$$V _{t}=\sqrt{2ax}.$$
then the force of weight only will affect it.
and use the same equation to get x 
$$\frac{ V _{i}^{2} }{ 2a }= x$$